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> So, what this tells me is, forget waiting for the 4 of one color
> in a row to happen -- that is irrelevant. But if you then just
> start from 0 and bet the same color each time, shouldn't your
> chance of winning at least once over "the next 5 bets" then be 97%?
Yes. Let's say you bet on black, and you want to know the chances of
winning at least once in the next 5 bets. If there is a 50-50 chance
of getting either color (no greens on this wheel), then the chances
of getting 5 REDS in a row, as we already discussed, are (1/2)^5 or
3.125%. Winning on at least one black means you DIDN'T get 5 reds in
a row, so the chances of winning at least once are the opposite of 5
reds in a row: 1-.03125 or 96.875%.
Gary
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