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>If you sum two all-pole filters you get zeros:
>
>F = A / ((1-w)*(1-x)) + B / ((1-y)*(1-z))
>
> = (A * (1-y)*(1-z) + B * (1-w)*(1-x)) / ((1-w)*(1-x)*(1-y)*(1-z))
Yup, mathematically you're right. I was thinking in terms of
summing them in the s-plane -- I don't see any place where the sum
goes to zero in that case. But you're right, if I do the conversion
substituting jw (w=omega) for s and multiplying H(s) by its complex
conjugate to get squared amplitude, I do get zeros.
-Alex
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