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At 08:59 PM 8/19/2004, Alex Matulich wrote:
>You might be interested to know that this was an all-pole filter
>with no zeros, constructed by summing two all-pole filters together
>in an attempt to get the overshoot of one to cancel out the lag of
>the other through destructive interference.
If you sum two all-pole filters you get zeros:
F = A / ((1-w)*(1-x)) + B / ((1-y)*(1-z))
= (A * (1-y)*(1-z) + B * (1-w)*(1-x)) / ((1-w)*(1-x)*(1-y)*(1-z))
Now the numerator is a second order polynomial with two roots (two zeros).
Bob Fulks
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