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I got that far (:-) but it doesn't have to be the very next bar.
Theoretically, it could take forever but that hasn't happened yet...
Cheers,
Ian
> {we need a bar that *closes* lower than either of
> > > the first two bars.}
>
>
> If C < C[1] or C < C[2] then begin
> IF H < SWINGHIGH(1,H,2,33)....
>
> On Thu, 19 Dec 2002 16:37 +0000 (GMT Standard Time)
> ianwaugh@xxxxxxxxx (Ian Waugh) wrote:
> > Gosh, is this as difficult as my limited EL abilities think it
> > is...?
> >
> > Cheers,
> > Ian
> >
> > > Hi All,
> > > I was wondering if someone a bit more versed in El than me
> > > could help with this.
> > >
> > > I'm trying to define a swing point, let's say a high, but it's
> > > not like a "standard" high that has a lower high on either side,
> > > I'd like to define a Swing high like this:
> > >
> > > A bar makes a higher high. The next bar can have the same high or
> > > a lower high but not, of course, a higher high. Then take the
> > > lowest low of these two bars. Now, in order to actually qualify
> > > that first bar as a swing high, we need a bar that *closes* lower
> > > than either of the first two bars.
> > >
> > > The minimum number of bars required to define a high is,
> > > therefore, three. However, theoretically, there's no limit to the
> > > maximum number of bars although in practise it's never reached
> > > the limit (:-).
> > >
> > > Having defined a swing high, we then look for a swing low which
> > > is defined in exactly the same way but, er, the other way around.
> > > You cannot have two SHs or two SLs in a row, the order must be
> > > SH, SL, SH, SL, etc.
> > >
> > > Well, I thought it was easy until I tried programming it...! But
> > > I'm sure I'm just missing one step of logic somewhere or other.
> > >
> > > I've be everso grateful if anyone could help out.
> > >
> > > Thanks.
> > >
> > > Cheers,
> > > Ian
> > >
> >
> >
>
>
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