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A:=mov(C,100,S);
B:=If(Sum(A>Ref(A,-1),11)>5,1,If(Sum(A<Ref(A,-1),11)>5,-1,0));
B;
B will =1 if a rising average, b will =-1 for a falling average
--- In equismetastock@xxxxxxxxxxxxxxx, "Roy Larsen" <rlarsen@xxx>
wrote:
>
> Hi Longhair
>
>
> I hate to disagree with Lionel but it seems to me that both options
say the same thing. That is that the 100-day SMA is rising. Applying
the delay to the moving average or the function being averaged makes
no difference, at least as set out in this simple scenario.
>
>
> Regards
>
> Roy
> www.metastocktops.co.nz
>
>
> ----- Original Message -----
> From: Lionel Issen
> To: equismetastock@xxxxxxxxxxxxxxx
> Sent: Friday, December 01, 2006 10:52 AM
> Subject: RE: [EquisMetaStock Group] Rising Moving Average
>
>
> Metastock ha a built in indicator MSU. It will give you better
answers.
>
> You should use more than a single day change to determine if a
moving
> average is rising
>
> Line 2 seems to be meaningless as as mov( today) will always be
equal to mov
> (ref(today))
>
> Lionel
>
> _____
>
> From: equismetastock@xxxxxxxxxxxxxxx
[mailto:equismetastock@xxxxxxxxxxxxxxx]
> On Behalf Of longhair4277
> Sent: Thursday, November 30, 2006 11:59 AM
> To: equismetastock@xxxxxxxxxxxxxxx
> Subject: [EquisMetaStock Group] Rising Moving Average
>
> Which of these 2 lines of code will tell me if the 100 day moving
> average is rising?
> 1.) mov( close , 100 , simple ) > mov( ref( close , -1 ) , 100 ,
> simple )
>
> 2.) mov( close , 100 , simple ) > ref( mov( close , 100 ,
simple ), -
> 1 )
>
> or is there a "simpler" way of doing this
>
> [Non-text portions of this message have been removed]
>
>
>
>
>
> [Non-text portions of this message have been removed]
>
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