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That is a different question.
You're initial question was "What is the probability of getting 5 consecutive
heads in 5 flips?" The answer is 1/(2^5).
The question in this comment is "What is the probability of getting at least 1
heads in a total of 5 flips?" Here, the answer is :
After first flip: 1/2
After second flip: 1/2 + (1/2)/2 = 0.75 (they could have come up HH, HT, TH, and
TT --- you would have gotten at least one heads in a total of two flips 3/4 of
the times)
After third flip: etc. = 0.875
...
After fifth flip: 1 - (1/2^5)
David Folster wrote:
> > In other words, if at any point you asked "what are the chances of
> > the NEXT 5 spins being black?" the answer would be 0.5^5. But if you
> > get 4 blacks in a row, and ask "what are the chances of the next 1
> > spin being black?" the answer is 50%.
>
> So, what this tells me is, forget waiting for the 4 of one color in a row to
> happen -- that is irrelevant. But if you then just start from 0 and bet the
> same color each time, shouldn't your chance of winning at least once over
> "the next 5 bets" then be 97%?
>
> Dave
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