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Seems like C is generally less than s or t, since s and t are defined
as peaks, so slope2 will generally be less than slope.
You may find some otherwise if you use a sizable data set.
Suggest you plot the zig-zag function to see where the peaks are to
get a feel for what is going on...
Ara
--- In amibroker@xxxx, "wdbaker8" <wdbaker8@xxxx> wrote:
> All,
> Attempting to figure out how to use the slope between two past
points
> and then buy when the slope between the farthest point and the
> current close becomes less than the slope between the original two
> points, I'm not getting any errors, just not getting anything at
> all. Thought maybe there was an obvious problem.
>
> Thanks for reviewing this and before you ask,
> I never finished high school so the slope equations etc... could be
> wrong.
>
> Thanks
> Bill Baker
> Filter=TimeNum()>=080000 AND TimeNum()<=150000;
> PositionSize=2500;
> s=Peak(Close,.01,3);
> t=Peak(Close,.01,2);
>
> slope=(t-s)/(BarsSince(s)-BarsSince(t));
> slope2=(C-s)/BarsSince(s);
> test1=slope2>slope AND s>t;
> Buy=Filter AND test1;
> Sell=TimeNum()>150000;
>
>
> Short=0;
> Cover=0;
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