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No, K was assigned the result of the first calculation X + Y
In the second calculation, the value of K to the right of the equal sign
now contains the result of the first calculation, so K is reassigned the
result of the new current value of K plus the current value of Z
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At 11:25 PM 04/25/2002 -0400, you wrote:
>k=x+y;
>k=k+z;
>
>the above are two lines from an ELA. does it mean that first compute k as
>x+y and then compute k again whatever x+y equals to, plus z?
>
>Thanks
>Romi
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