RE: use IF statement, return nul value

["Liu, Marshall" <LiuM@xxxxxxx>]

I think you can use the alert function:

Press Help then select Index and type in Alert:

SYNTAX	alert( EXPRESSION, PERIODS )

FUNCTION	Extends a "true" result of EXPRESSION for the specified
number of periods.  This true result is held true over the
number of periods specified even if a "false" result is generated. 

EXAMPLE	alert( cross(rsi(14),70),5 )

SEE ALSO	See Using the Alert() Function

for information on using the Alert function within a system test.

Thanks,
Marshall M. Liu


-----Original Message-----
From: neo [mailto:neo1@xxxxxxxxx]
Sent: Friday, January 26, 2001 12:20 PM
To: metastock@xxxxxxxxxxxxx
Subject: RE: use IF statement, return nul value


Bob

I tried everything on this a little while ago and called MS support. It is
not possible. What I has to do what make up a null indicator that is 0. I
then plot this as the last indicator with a gray line and this covers up the
0 points.

neo


-----Original Message-----
From: owner-metastock@xxxxxxxxxxxxx
[mailto:owner-metastock@xxxxxxxxxxxxx]On Behalf Of Bob Webb
Sent: Thursday, January 25, 2001 9:29 AM
To: metastock@xxxxxxxxxxxxx
Subject: use IF statement, return nul value


I want to use an IF Statement in an indicator.

But I want the "else" part of the statement to return nothing... a nul
value, and not a 0 (zero) nor anything else.

Reason: What I want to plot is a point over the bar when a condition is
met, and to plot nothing when the condition is not met. If you put a 0
(zero) as the "else" part of the statement, then the indicator plots a zero
at the bottom of the graph; I don't want this.

Can you help?

Bob.


==============+==============
Robert L. Webb
Webb.Bob@xxxxxxxx
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