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Try using Sum(cond1 and cond2 and cond3 and cond4,ndays)>=3;
  ----- Original Message ----- 
  From: Yuki Taga 
  To: amibroker@xxxxxxxxxxxxxxx 
  Sent: Wednesday, September 22, 2004 8:20 AM
  Subject: [amibroker] need any 3 of 4 conditions to be true
  If I define four conditions, how can I write a filter statement that returns
  issues where *any* 3 of the 4 conditions are true?
  For example:
  Cond1 = whatever;
  Cond2 = wherever;
  Cond3 = whomever;
  Cond4 = however;
  filter = (need *any* 3 of the 4 above to be true);
  I think I could eventually get this done myself, but I suspect the
  result would make a programmer roll on the floor with laughter.  The
  only way I can think of to do it would be *really* long.  There must
  be a compact way of doing this, isn't there?
  Yuki
  Check AmiBroker web page at:
  http://www.amibroker.com/
  Check group FAQ at: http://groups.yahoo.com/group/amibroker/files/groupfaq.html 
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