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Hi, you are using the ROC as a variable, but the MS detect it as a built in function and waiting for the completion of the ROC function, either use deferent variable in two locations for the ROC or add any thing to it, i.e. ROCA.
your code will look like attached file.
thanks
jao...
Paul Harris <paul_vicmar@xxxxxxxxxxx> wrote:
Thanxs Roy
Changed to Rocd, and no problems.
PAUL
--- In equismetastock@xxxxxxxxxxxxxxx, "Roy Larsen" <rlarsen@xxx> wrote:
>
> Hi Paul
>
>
> Roc cannot be used as a variable name because it is a reserved
function name - ROC().
>
>
> Regards
>
> Roy
> www.metastocktips.co.nz
>
>
> ----- Original Message -----
> From: Paul Harris
> To: equismetastock@xxxxxxxxxxxxxxx
> Sent: Friday, July 06, 2007 8:13 PM
> Subject: [EquisMetaStock Group] Problems with this code
>
>
> Preston et al
> I have problems with this code as it is rejected by MS. And I can?t
> see why.
>
> DemandInd:= If(Dema(DI(),8) > 5,+1,If(Dema(DI(),8) < -13,-1,0));
> LinReg:= If(Dema(10000*LinRegSlope(C,13)/C,13) > 5,+1,
> If(Dema(10000*LinRegSlope(C,13)/C,13) < -13,-1,0));
> Roc:= If(Dema(ROC(C,8,%),8) > 2,+1,If(Dema(ROC(C,8,%),8) < -2,-1,0));
> Mon:= If(Dema(MFI(8),8)-50 > 5,+1,If(Dema(MFI(8),8)-50 < -5,-1,0));
> DemandInd+LinReg+Roc+Mon
>
> Anyone see what the problem is.
> Thanxs
> PAUL
>
>
>
>
>
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