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have you tried a simpler method?
array = RSI(21);
Threshold = 50;
count = barssince(array>=threshold);
--
Cheers
Graham Kav
AFL Writing Service
http://www.aflwriting.com
On 27/09/2007, Rick Osborn <ricko@xxxxxxxxxx> wrote:
> You are correct (typo) - but fixing that doesn't solve
> my initial problem
>
> --- Ara Kaloustian <ara1@xxxxxxxxxx> wrote:
>
> > Seem to be missing a ";" after "count = 0".
> >
> > You should be getting an error message.
> >
> > ----- Original Message -----
> > From: "ricko8294_98" <ricko@xxxxxxxxxx>
> > To: <amibroker@xxxxxxxxxxxxxxx>
> > Sent: Wednesday, September 26, 2007 7:34 PM
> > Subject: [amibroker] Loop Problem
> >
> >
> > > What is wrong with this code? The concept seems
> > to simple and it's
> > > driving me nuts.
> > >
> > > I want to count the number of consecutive days an
> > array, (say RSI(21)
> > > is above a threshhold, (say 50) but to revert to
> > zero if it falls
> > > below that threshhold.
> > >
> > > Here is the code, which does not seem to work.
> > The value of "Count"
> > > always seems to be zero.
> > >
> > >
> > >
> > > array = RSI(21);
> > > Threshold = 50;
> > > ConsecutiveDays = 10;
> > > Count = 0 // initialize
> > >
> > > for (i = 1; i < ConsecutiveDays + 1; i++)
> > > {
> > >
> > > if (Array[i] >= Threshold[i]) Count[i] =
> > Count[i-1] + 1;
> > >
> > > else Count[i] = 0;
> > > }
> > >
> > >
> > > Thanks
> > > Rick
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