[amibroker] Re: getting an error in my if statement

["lifes_student_1" <suedeuno@xxxxxxxxx>]

It's a bit more complicated than my example. I need to check for 
several cases and I would generally use an if statement for something 
like this. Something like:

result = false;
if (trigger == true)
{
 if (c1 == true)
 {
  if (c2 == true)
  {
     result = true;
  }
 }
}

--- In amibroker@xxxxxxxxxxxxxxx, Graham <kavemanperth@xxx> wrote:
>
> Not knowing what you are trying to do why not try the simpler and
> faster IIF function
> 
> -- 
> Cheers
> Graham Kav
> AFL Writing Service
> http://www.aflwriting.com
> 
> 
> 
> On 26/08/07, lifes_student_1 <suedeuno@xxx> wrote:
> > Thanks. Why can't I do the following though that should result in 
a
> > boolean:
> >
> > color = colorLime;
> > color2 = colorRed;
> > i1 = colorLime;
> > c1 = ((i1 == color OR i1 == color2));
> > if (c1 == true)
> > {...
> >
> >
> > This doesn't work. I guess I'm not used to AFL.
> >
> >
> >
> > --- In amibroker@xxxxxxxxxxxxxxx, "Thomas Z." <tzg@> wrote:
> > >
> > > You need a loop and then you could write if(barsback[i] < 6)
> > >
> > > The other way would be to use IIF()
> > >
> > > Regards
> > > Thomas
> > > www.patternexplorer.com
> > >
> > >
> > >
> > > From: amibroker@xxxxxxxxxxxxxxx 
[mailto:amibroker@xxxxxxxxxxxxxxx]
> > On Behalf
> > > Of lifes_student_1
> > > Sent: Saturday, August 25, 2007 8:28 PM
> > > To: amibroker@xxxxxxxxxxxxxxx
> > > Subject: [amibroker] getting an error in my if statement
> > >
> > > condition1 = cross(close, ma(close,20));
> > > barsback = BarsSince(condition1 == true);
> > > if(barsback < 6)
> > > {...
> > >
> > > I'm getting error 6 on barsback in if statement. condition1 is 
set
> > and
> > > works as I've tested it elsewhere. What am I doing wrong?
> > >
> > > (Condition in IF, WHILE, FOR statements has to be Numeric or
> > Boolean
> > > type. You cannot use an array here....)
> > >
>




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