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That works fine for me. What error is it giving?
You don't need the two sets of brackets in the "c1 = ..." statement
though.
Regards,
GP
--- In amibroker@xxxxxxxxxxxxxxx, "lifes_student_1" <suedeuno@xxx> wrote:
>
> Thanks. Why can't I do the following though that should result in a
> boolean:
>
> color = colorLime;
> color2 = colorRed;
> i1 = colorLime;
> c1 = ((i1 == color OR i1 == color2));
> if (c1 == true)
> {...
>
>
> This doesn't work. I guess I'm not used to AFL.
>
>
>
> --- In amibroker@xxxxxxxxxxxxxxx, "Thomas Z." <tzg@> wrote:
> >
> > You need a loop and then you could write if(barsback[i] < 6)
> >
> > The other way would be to use IIF()
> >
> > Regards
> > Thomas
> > www.patternexplorer.com
> >
> >
> >
> > From: amibroker@xxxxxxxxxxxxxxx [mailto:amibroker@xxxxxxxxxxxxxxx]
> On Behalf
> > Of lifes_student_1
> > Sent: Saturday, August 25, 2007 8:28 PM
> > To: amibroker@xxxxxxxxxxxxxxx
> > Subject: [amibroker] getting an error in my if statement
> >
> > condition1 = cross(close, ma(close,20));
> > barsback = BarsSince(condition1 == true);
> > if(barsback < 6)
> > {...
> >
> > I'm getting error 6 on barsback in if statement. condition1 is set
> and
> > works as I've tested it elsewhere. What am I doing wrong?
> >
> > (Condition in IF, WHILE, FOR statements has to be Numeric or
> Boolean
> > type. You cannot use an array here....)
> >
>
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