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Hello,
Jayson: I really appreciate your posts. I was just about
to answer some questions on the mailing list
but...I found almost all of them answered already by you and
other active members of this group.
Thank you!
I am quite busy now working on new data plugins and (finally)
on new SDK to be released in November.
Markus:
1. First of all
x=llv(low,5) does not constitute boolean condition. It does
give you lowest low from 5 recent bars.
You should use
x = LLV( Low, 5 ) == Low;
or
x = LLVBars( Low, 5 ) == 0;
2. Second thing:
"Now, I want to find the high of condition 2 that occured
right before the low of condition 1. Thus, cum(1) of condition 2 is less than
that of condition 1."
There are other functions for that:
cond1 = LLVBars( Low, 5 ) ==
0;
// to get the Highest point since cond1 is true you can
use:
HighestSince( cond1, High );
if you want to get the 5 bar highest since cond1 is
true
ValueWhen( Ref( cond1, -5 ), HighestSince( cond1, High )
);
You may add your Cum(1)>150
clause to filter out first 150 bars if you wish
3. Last thing:
it is better to describe entire system (not just single-line
problem) because
it is easier to provide valuable reply
then.
Best regards,Tomasz Janeczkoamibroker.com
<BLOCKQUOTE
>
----- Original Message -----
<DIV
>From:
IVA GmbH
To: <A title=amibroker@xxxxxxxxxx
href="">amibroker@xxxxxxxxxxxxxxx
Sent: Wednesday, October 30, 2002 12:19
AM
Subject: Re: [amibroker] Where´sthe
flaw?
Jayson,
appreciate your ongoing "tech
support"!
Well, the code is part of an exploration-
correct.
Your first solution dosn´t work since it suggests
that only symbols with mroe than 150 days of price data are included, if I
understand it properly.
The second soluation comes close and I also
thought of it as well.
Question back: is it enough to require that the
cum value equals 150 or wouldn´t it be correct to require that the cum value
of condition 1 (here: 150) is larger than the one of
condition two?
Let me give an example:
x=llv(low,5)
condition 1=valuewhen(x,cum(1),1);
y=hhv(high,5)
condition 2=valuewhen(y,cum(1),1);
Now, I want to find the high of condition 2 that
occured right before the low of condition 1. Thus, cum(1) of condition 2 is
less than that of condition 1.
One more specification is necessary, andthis is
where my problem kicks in: I have to find the first instance where y applies
AND where its cum value is smaller than that of condition 1.
Are you lost?
Markus
----- Original Message -----
<BLOCKQUOTE
>
<DIV
>From:
<A title=jcasavant@xxxx
href="">Jayson
To: <A title=amibroker@xxxxxxxxxxxx
href="">amibroker@xxxxxxxxxxxxxxx
Sent: Tuesday, October 29, 2002 6:34
PM
Subject: RE: [amibroker] Where´s the
flaw?
<FONT
face=Arial size=2><FONT face=Arial
size=2><FONT face=Arial
size=2>
<SPAN
class=010122817-29102002>Marcus,
<SPAN
class=010122817-29102002>this is an exploration??
try.......
<SPAN
class=010122817-29102002>
<SPAN
class=010122817-29102002>filter=cum(1)>150;
<SPAN
class=010122817-29102002>valuewhen(condition2,low,1)
<SPAN
class=010122817-29102002>
or
alternatively
<SPAN
class=010122817-29102002>
<SPAN
class=010122817-29102002>valuewhen(cum(1)>150 and
condition2,low,1)
Jayson
<FONT face=Tahoma
size=2>-----Original Message-----From: <A
href="">funnybiz@xxxx
[mailto:funnybiz@xxxx]Sent: Tuesday, October 29, 2002 12:07
PMTo: <A
href="">amibroker@xxxxxxxxxxxxxxxSubject:
[amibroker] Where´s the flaw?
Folks,
I´m trying to tell AB that one condition show
come before another. My criteria of defining "b3fore" is the cum value of
thope two conditions of which the first one has -let´s say- a cum value 0f
150.
This doens´t work, and I don´t know
why:
<FONT face=Arial
size=2>Valuewhen(iif(condition2,cum(1),0)<150,low,1)
I´m trying to determine the low for the day on
which condition two is fulfilled which should show a cum value <150 AT
THE FIRST instance since condition 2 might ocur several times with a cum
value smaller than 150!
Any ideas why it soesn´t wanna
work????
Appreciate it!
MarkusPost
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