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sorry to answer late, you're right in that( your) case,
example:
slope=
(Trough(L,7,1) - Trough(L,7,2)) /
(TroughBars(L,7,2) - TroughBars(L,7,1));
Stephane
> I am probably just mis-communicating, The first part of the
equation
> (5-1) should always be the opposite way(1-5) or (recent price -
less
> recent price) and that would always establish if the slope is
> positive or negative depending on if price were rising or falling,
> then it would alway be divided by the period(20-2) or abs(2-20)
which
> would always be a positive #.
>
> Hope that makes more sense
> wdbaker
> --- In amibroker@xxxx, "Stephane Carrasset" <nenapacwanfr@xxxx>
wrote:
> > suppose 20 days ago the close is 5$
> > and 2 days ago the close is 1$
> >
> > the slope of the price must be negative 1$ is less than 5$
> > BUT
> > (5-1)/ (20-2) is positive
> >
> >
> > Stephane,
> > > I have less than a highschool education so that could be
getting
> in
> > > the way but I think that the first part of the equation
> determines
> > if
> > > the slope is positive or negative, the last part of the
equation
> > just
> > > establishes the period to divide by to get the slope. I just
> > > recently began studying this though so could be wrong.
> > >
> > > Thanks
> > > wdbaker
> > > --- In amibroker@xxxx, "Stephane Carrasset"
<nenapacwanfr@xxxx>
> > wrote:
> > > >
> > > >
> > > > > the w & y issue, I think the equation goes slope=(endval-
> > > startval)/
> > > > > (time or bars) and the way you have it written would give
me
> a
> > > > > negative # of bars I think.
> > > >
> > > > yes, negative and
> > > > if endval-startval is positive ( startval< endval)the slope
is
> > > > negative and
> > > > if endval-startval is negative( startval>endval) the slope
is
> > > positive
> > > >
> > > > why do you want that the slope is always positive??
> > > >
> > > > stephane
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